2014-2015 1. 3 2.i didn't get how to do it:( 2015-2016 1.108???? 2.I have no idea about this one.

2010-2011: 3)00001 4)01110 2012-2013: 3)00000 4)11000

Questions: 1) 42 2) 22 3)20026 4) B 5) Idk Coding: 1) Say that s is the only digit after the very last zero in the code. 2) It makes s its own char in the array. 3) It defines the largest char and that largeIndex is = i. 4)Yes

5) A= 5 B= 6 C= 5 D= 12 2) 6 1)44

import java.util.*; class Main { public static int points(String letter){ int points=0; switch(letter){ case "A": points=1;break; case "E": points=1;break; case "D": points=2;break; case "R": points=2;break; case "B": points=3;break; case "M": points=3;break; case "V": points=4;break; case "Y": points=4;break; case "J": points=8;break; case "X": points=8; } return points; } public static int letterMul(int num){ int mul =1; if(num==3||num==9||num==15||num==21||num==27||num==33||num ==39){ mul=2; } else if (num==5||num==10||num==20||num==25||num==30||num==35||num==40){ mul=3; } return mul; } public static int wordMul(int num){ int mul =1; if(num==7||num==14||num==28){ mul=2; } else if (num==8||num==16||num==24||num==32){ mul=3; } return mul; } public static void main(String[] args) { Scanner input = new Scanner(System.in); String[] letters = new String[4]; for(int i=0;i<4;i++){ letters[i]=input.next(); } input.nextLine(); for (int k=0;k<6;k++){ int total=0; int word =1; int start=input.nextInt(); String hotspot= input.next(); for(int i=0;i<4;i++){ total+=points(letters[i])*letterMul(start+i); if (hotspot == "H"){ if(wordMul(start+i)>word){ word=wordMul(start+i); } } if(hotspot == "V"){ if(wordMul(start+(i*10))>word){ word=wordMul(start+(i*10)); } System.out.println(total*word); } } } } }

I think it's for both classes

R7.6 a. 1,2,3,4,5,4,3,2,1,0 b. 1,3,5,3,1 c . 2,4,4,2,0 d. 2,3,4,5,4,3,2,1,0 e. 2,4,6,8,10,8,6,4,2,0 f. 0,1,2,3,4,5,4,3,2,1 g. 0,2,4,4,2 h. same as a. R.7.7 a. 0,1,2,3,4,3,2,1,0,-1 b. 1,2,3,4,5,4,3,2,1,0 c. 2,3,4,5,6,5,4,3,2,1 d. 1,2,3,4,5,4,3,2,1,0 e. 1,3,4,5,6,5,4,3,2,1 f. 0,0,0,0,0 g. 1,2,3,4,5 h. 2,3,4,5 R7.10 a. There are no values in the array and there is no system.out.print and out of bound error b. The array has no length for it to say values.length

R7.3 Nothing happens. The code doesn't get run through. R7.2 a. The location of an item in an array b. integer values between 0 and the array's length - 1 c. A bounds error is a runtime error R7.4 I didn't know how to this.

R6.2 a. 0 10 b. 10,12,14,16,18,20... 1 9 2 8 3 7 4 6 R.6.1 a. * ** *** **** b. ===== * ==== ** === *** == **** = c. ***** ***** ***** ***** ***** ... R6.22 a. 10 b.1.925 c.error d.error

R6.3 a. 1 b. 0 c. 5 d. 2 R6.5 ? R6.7 a. 9 b. error c. 2 d. 9 e. 8 f. error R6.21 a. 6 b. 1 c. 6 5

R5.2) The first code has both if statements but the second code has one if and an else if statement R5.4) a. m b. n c. error d. error R5.3) a. It says then which it shouldn't b. It didn't close the brackets c. There has to be double = signs d. In the if statement the String is not the same as the x String e. There is no default statement in the code.

1) Is a text scanner. 2) Says that the next line should be the name. 3) The answer of the boolean question.

R2=0, R3= Mystery has already been defined as an int so there's no need to define it again, R4= I couldn't get this one bc it kept showing error all the time, R1= a=int, constant. c=int, constant. b=float int. d=float int.

If you change the value of x then the value of v does not change, because you are just multiplying x times 10 and then dividing that solution by x to get v which = 3. So, the value of v does not change.