int firstInt = (int) Math.log10(x); int a = (int) (x / Math.pow(10, firstInt)); int b = x%10; System.out.print("The outer digits are " + a + " and " + b);

1. this is a compile time error, but readInt doesn't exist, nextInt does though 2. after the second System.out.print, x should be y 3. the scanner shouldn't be initialized with a string

1. A6 2. 4DE 3. a) 100010 b) 11010 c) 1011100 d) 1011 e) 10001100; bcd 4. 168C18 5. 10001001111 6. 5

double d = 12; double c = 10; double h = d/2-Math.sqrt((d/2)*(d/2) - (c/2) * (c/2)); System.out.print((2*c*h/3)+((Math.pow(h, 3))/(2*c)));

100111; 10111111 10011; -10101 100100010; 10001100110010 10; 1

11, 13, 15, 17, 25, 787, 571 1111011, 1100010101, 10001100111101, 10001000111010, -11110100001001000000, 0.1

class quadraticEquation { public static void main() { int a=2; int b=-1; int c=-21; System.out.println("x=" + ((-b + Math.sqrt(b*b - 4*a*c))/(2*a)) + " or " + ((-b - Math.sqrt(b*b - 4*a*c))/(2*a))); } } x=3.5 or -3.0

double money = 2000; int years = 1; String finalMoney1; String roundedMoney; String finalMoney2; while(years <= 20){ money = money * 1.05; years ++; } finalMoney1 = Double.toString(money); roundedMoney = finalMoney1.substring(finalMoney1.indexOf('.') + 1, finalMoney1.indexOf('.') + 3) + "." + finalMoney1.substring(finalMoney1.indexOf('.') + 3, finalMoney1.indexOf('.') + 4); money = (int) Math.round(Double.parseDouble(roundedMoney)); finalMoney2 = finalMoney1.substring(0, finalMoney1.indexOf('.') + 1) + money System.out.println("$" + finalMoney2.substring(0, finalMoney2.length()-2)); $5306.60