2022 - 2023 Class 22 | Legion of Learners

Essentially iterate through each cell in the array and each of the 3x3 cells around it and if it meets the conditions for survival. Keep a running number of surviving cells and the number of cells around each.

Solution to HW problem on Slide 4:

Essentially follow the instructions and use a list to do elementwise operations on the string

x = list(input('A'))
num = int(input('A'))
for i in range(num):
  key = input('A')
  key_int = int(key,16)
  print(''.join(x))
  ind1 = int(str(key_int)[1])
  ind2 = int(str(key_int)[2])
  print(ind1,ind2)
  if int(str(key_int)[0]) %2 ==0:
    a = x[ind1-1] 
    x[ind1-1] = x[ind2-1]
    x[ind2-1] = a
  else:
    a = x[-ind1] 
    x[-ind1] = x[-ind2]
    x[-ind2] = a
  if i==0:
    x = ['A'] +x + ['A','A']
  x = [key[0]] + x + [key[2]]
ind = int(input('A'))-1
  
print(x[ind], ''.join(x))