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Simplify the following boolean algebra expression:
~( ~ (A + BC) + ~ (A * ~ B)) = ~~(A + BC) * ~~ (A * ~ B) = (A + BC)(A * ~ B) = A + B*~BC = A
~( ~ (A + BC) + ~ (A * ~B)) = (~~(A + BC)(~~(A * ~ B)) = (A + BC)(A * ~B) = A(1 + BC)(~B) = A(~B)
~( ~ (A + BC) + ~ (A * ~ B)) = ~~(A + BC) * ~~ (A * ~ B) = (A + BC)(A * ~ B) = A + B*~BC = A